LemmyLaLibre@feddit.ch to Memes@lemmy.ml · 2 years agoI say double it.feddit.chimagemessage-square134fedilinkarrow-up1775
arrow-up1753imageI say double it.feddit.chLemmyLaLibre@feddit.ch to Memes@lemmy.ml · 2 years agomessage-square134fedilink
minus-squareghariksforge@lemmy.worldlinkfedilinkarrow-up41·2 years agoAt some people you will run out of people to tie to the tracks.
minus-squareDiplomjodler@feddit.delinkfedilinkarrow-up11·2 years agoHow many branches is that going to take? Just out of interest.
minus-squarealerternate@lemmy.worldlinkfedilinkarrow-up22·2 years agomath checks out. log2(8 billion) ~= 32.9
minus-squareghariksforge@lemmy.worldlinkfedilinkarrow-up9arrow-down2·2 years agoIt’s a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.
minus-squareSabazius@lemmy.worldlinkfedilinkarrow-up7·edit-22 years agoIt’ll just be one fewer junctions. 2^n is always one more than the sum of 21+…2(n-1)
minus-squareMagikjak@lemmy.worldlinkfedilinkarrow-up1·2 years agoI think you have to include 2^0 for that to be true? e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.
minus-squareghariksforge@lemmy.worldlinkfedilinkarrow-up3·edit-22 years ago2^33 is approximately 8.5 billion, which is roughly the population of the world.
minus-squareℛ𝒶𝓋ℯ𝓃@pawb.sociallinkfedilinkarrow-up5·2 years agoSo the 32nd person decides to either kill half of humanity and end the scenario, or give someone the power to end human kind…
minus-squareMeetInPotatoes@lemmy.mllinkfedilinkEnglisharrow-up4·2 years agoLong before that, you’d run out of track to tie to the people.
minus-squareatlasraven31@lemm.eelinkfedilinkarrow-up1arrow-down1·2 years agoA later choice of nobody on each track would be ideal. Even a psycho at the switch would be unable to kill.
At some people you will run out of people to tie to the tracks.
How many branches is that going to take? Just out of interest.
Only 32
math checks out. log2(8 billion) ~= 32.9
It’s a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.
It’ll just be one fewer junctions. 2^n is always one more than the sum of 21+…2(n-1)
I think you have to include 2^0 for that to be true?
e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.
2^33 is approximately 8.5 billion, which is roughly the population of the world.
So the 32nd person decides to either kill half of humanity and end the scenario, or give someone the power to end human kind…
🤣
Long before that, you’d run out of track to tie to the people.
A later choice of nobody on each track would be ideal. Even a psycho at the switch would be unable to kill.