LemmyLaLibre@feddit.ch to Memes@lemmy.ml · 1 year agoI say double it.feddit.chimagemessage-square134fedilinkarrow-up1775
arrow-up1753imageI say double it.feddit.chLemmyLaLibre@feddit.ch to Memes@lemmy.ml · 1 year agomessage-square134fedilink
minus-squareghariksforge@lemmy.worldlinkfedilinkarrow-up41·1 year agoAt some people you will run out of people to tie to the tracks.
minus-squareDiplomjodler@feddit.delinkfedilinkarrow-up11·1 year agoHow many branches is that going to take? Just out of interest.
minus-squarealerternate@lemmy.worldlinkfedilinkarrow-up22·1 year agomath checks out. log2(8 billion) ~= 32.9
minus-squareghariksforge@lemmy.worldlinkfedilinkarrow-up9arrow-down2·1 year agoIt’s a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.
minus-squareSabazius@lemmy.worldlinkfedilinkarrow-up7·edit-21 year agoIt’ll just be one fewer junctions. 2^n is always one more than the sum of 21+…2(n-1)
minus-squareMagikjak@lemmy.worldlinkfedilinkarrow-up1·1 year agoI think you have to include 2^0 for that to be true? e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.
minus-squareghariksforge@lemmy.worldlinkfedilinkarrow-up3·edit-21 year ago2^33 is approximately 8.5 billion, which is roughly the population of the world.
minus-squareℛ𝒶𝓋ℯ𝓃@pawb.sociallinkfedilinkarrow-up5·1 year agoSo the 32nd person decides to either kill half of humanity and end the scenario, or give someone the power to end human kind…
minus-squareMeetInPotatoes@lemmy.mllinkfedilinkEnglisharrow-up4·1 year agoLong before that, you’d run out of track to tie to the people.
minus-squareatlasraven31@lemm.eelinkfedilinkarrow-up1arrow-down1·1 year agoA later choice of nobody on each track would be ideal. Even a psycho at the switch would be unable to kill.
At some people you will run out of people to tie to the tracks.
How many branches is that going to take? Just out of interest.
Only 32
math checks out. log2(8 billion) ~= 32.9
It’s a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.
It’ll just be one fewer junctions. 2^n is always one more than the sum of 21+…2(n-1)
I think you have to include 2^0 for that to be true?
e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.
2^33 is approximately 8.5 billion, which is roughly the population of the world.
So the 32nd person decides to either kill half of humanity and end the scenario, or give someone the power to end human kind…
🤣
Long before that, you’d run out of track to tie to the people.
A later choice of nobody on each track would be ideal. Even a psycho at the switch would be unable to kill.